(noch nicht übersetzt)

Problem 911

An irrational number x can be uniquely expressed as a continued fraction [a0;a1,a2,a3,]: x=a0+1a1+1a2+1a3+where a0 is an integer and a1,a2,a3, are positive integers.

Define kj(x) to be the geometric mean of a1,a2,,aj.
That is, kj(x)=(a1a2aj)1/j.
Also define k(x)=limjkj(x).

Khinchin proved that almost all irrational numbers x have the same value of k(x)2.685452 known as Khinchin's constant. However, there are some exceptions to this rule.

For n0 define ρn=i=02n22iFor example ρ2, with continued fraction beginning [3;3,1,3,4,3,1,3,], has k(ρ2)2.059767.

Find the geometric mean of k(ρn) for 0n50, giving your answer rounded to six digits after the decimal point.